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Enable solar power systems to provide sufficient power for loads
Jun 04, 2018

At present, crystalline silicon materials (including polysilicon and monocrystalline silicon) are the most important photovoltaic materials, with a market share of over 90%, and they will continue to be the mainstream material for solar cells for quite a long time to come.

The production technology of polysilicon materials has long been in the hands of 10 factories in 7 companies in 3 countries including the United States, Japan, and Germany, resulting in a technological blockade and market monopoly.

The demand for polysilicon mainly comes from semiconductors and solar cells. According to different purity requirements, it is divided into electronic and solar energy grades. Among them, for electronic grade polysilicon accounted for about 55%, solar grade polysilicon accounted for 45%.

The solar AC power generation system is composed of solar panels, charge controllers, inverters, and batteries; solar DC power generation systems do not include inverters. In order for the solar power system to provide sufficient power for the load, it is necessary to properly select each component according to the power of the electrical appliance. The following uses the 100W output power, taking 6 hours per day as an example, to introduce the calculation method:

1. First calculate the watt-hours consumed per day (including inverter losses): If the inverter conversion efficiency is 90%, when the output power is 100W, the actual output power should be 100W/90 %=111W; if used for 5 hours per day, the power consumption is 111W*5 hours=555Wh.

2. Calculation of solar panels: Calculated according to the daily effective sunshine time of 6 hours, and then taking into account the charging efficiency and the loss during the charging process, the output power of the solar panel should be 555Wh/6h/70%=130W. 70% of this is the actual power used by the solar panel during the charging process.


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